If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0.4x^2-1.6x-12.8=0
a = 0.4; b = -1.6; c = -12.8;
Δ = b2-4ac
Δ = -1.62-4·0.4·(-12.8)
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{23.04}}{2*0.4}=\frac{1.6-\sqrt{23.04}}{0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{23.04}}{2*0.4}=\frac{1.6+\sqrt{23.04}}{0.8} $
| u+3/u+5=(u-2/u+2)+1 | | 2(a-5)=15 | | 13+x=105 | | -h/3-4=-1 | | 1/15x−4/5=2/3 | | 4-2x=-x+4 | | 9(x+2)-6(x-1)+14=5(x-3+11 | | 25+n=19 | | 6(×-8)=7(x-3) | | 6.7x=5.2+12.5 | | 7x-3x+7=3x+6+20 | | 8+9p=9-7 | | 0=t^2+4t-3 | | 0.6(2m-10)=0.7m+10 | | 2/3x+18=14 | | 8-(x+5)=12 | | -16(x-5)=4(x+5 | | 4z+36=3(4z+2) | | 8+8p=9p-7 | | x*40=40+x | | 3(1-3G=-8g+14 | | 4x-7+5x-6=113 | | 4x+6(x-8)=-118 | | 25(x-3)=-8x^2 | | 130+0.70x=70x+0.90 | | (19-y)+5y=59 | | 3(-7+8x)+5=-184 | | -3(x+5)+5=2(x-6) | | x*40=80 | | 80=-4(4-4x) | | 2x^2+28x=96 | | 172=4(1+7a) |